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Xbase++ : BAnd() / BOr() / BXOr()
Posted: Wed Oct 23, 2019 11:00 pm
by AUGE_OHR
more Xbase++ to harbour Question
BAnd( <nVa1>, <nVal2>, [<nVal3>,...] ) -> nBitwiseAnd
BOr( <nVa1>, <nVal2>, [<nVal3>,...] ) -> nBitwiseOr
BXOr( <nVa1>, <nVal2>, [<nVal3>,...] ) -> nBitwiseXOr
what to use with harbour
Re: Xbase++ : BAnd() / BOr() / BXOr()
Posted: Thu Oct 24, 2019 5:37 am
by edk
hb_BitAnd(<nVal1>, <nVal2> [, <nVal3>, ... ]) ➜ nResult
performs a bitwise AND operation, same as & operator in C language.
hb_BitNot(<nVal>) ➜ nResult
returns the bitwise complement of <nVal> (all bits are flipped), same as ~ operator in C language.
hb_BitOr(<nVal1>, <nVal2> [, <nVal3>, ... ]) ➜ nResult
performs a bitwise OR operation, same as | operator in C language.
hb_BitXor(<nVal1>, <nVal2> [, <nVal3>, ... ]) ➜ nResult
performs a bitwise XOR operation, equivalent of ^ operator in C language.
Re: Xbase++ : BAnd() / BOr() / BXOr()
Posted: Thu Oct 24, 2019 9:08 pm
by AUGE_OHR
hi,
that is easy, THX
Code: Select all
#xtranslate BAND => hb_BitAnd
#xtranslate BOr => hb_BitOr
#xtranslate BXOr => hb_BitOr
#xtranslate BNot => hb_BitNot