Xbase++ : BAnd() / BOr() / BXOr()

[AUGE_OHR]

more Xbase++ to harbour Question

BAnd( <nVa1>, <nVal2>, [<nVal3>,...] ) -> nBitwiseAnd
BOr( <nVa1>, <nVal2>, [<nVal3>,...] ) -> nBitwiseOr
BXOr( <nVa1>, <nVal2>, [<nVal3>,...] ) -> nBitwiseXOr

what to use with harbour

[edk]

hb_BitAnd(<nVal1>, <nVal2> [, <nVal3>, ... ]) ➜ nResult
performs a bitwise AND operation, same as & operator in C language.

hb_BitNot(<nVal>) ➜ nResult
returns the bitwise complement of <nVal> (all bits are flipped), same as ~ operator in C language.

hb_BitOr(<nVal1>, <nVal2> [, <nVal3>, ... ]) ➜ nResult
performs a bitwise OR operation, same as | operator in C language.

hb_BitXor(<nVal1>, <nVal2> [, <nVal3>, ... ]) ➜ nResult
performs a bitwise XOR operation, equivalent of ^ operator in C language.

[AUGE_OHR]

hi,

that is easy, THX

Code: Select all

   #xtranslate BAND                            =>  hb_BitAnd
   #xtranslate BOr                             =>  hb_BitOr
   #xtranslate BXOr                            =>  hb_BitOr
   #xtranslate BNot                            =>  hb_BitNot